The number of concurrent users of a social networking site has increased dramatically since 2002. By 2011, this social networking site could connect concurrently 70 million users online. The function $P(t)=2.575(1.487)^{t}$, where $t$ is the number of years after 2002, models this increase in millions of users. Estimate the number of users of this site that could be online concurrently in 2003, in 2007, and in 2010. Round to the nearest million users.
The number of users of this site that could be online concurrently in 2003 is approximately $\square$ million. (Round to the nearest whole number.)
Answer
Final Answer: The number of users of this site that could be online concurrently in 2003 is approximately \(\boxed{4}\) million.
Step 1 ：The problem asks for the number of users that could be online concurrently in 2003. We can use the given function \(P(t)=2.575(1.487)^{t}\) to calculate this. The variable \(t\) represents the number of years after 2002, so for 2003, \(t=1\).
Step 2 ：Substitute \(t=1\) into the function, we get \(P(1)=2.575(1.487)^{1}\).
Step 3 ：Calculate the value of \(P(1)\), we get \(P(1) = 3.8290250000000006\).
Step 4 ：Round \(P(1)\) to the nearest whole number, we get \(P(1) = 4\).
Step 5 ：Final Answer: The number of users of this site that could be online concurrently in 2003 is approximately \(\boxed{4}\) million.
