The polynomial
\[
p(x)=x^{3}-6 x^{2}+11 x-6
\]
has three real roots. List them in increasing sequence:
Hint: Find one of the roots by trial and error (it's easy for this problem), use synthetic division, and finish by solving a quadratic equation.
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Answers (in progress)
The roots of the polynomial \(p(x)=x^{3}-6 x^{2}+11 x-6\) in increasing sequence are \(\boxed{1, 2, 3}\).
Step 1 :First, we find one of the roots by trial and error. Since the coefficients of the polynomial are small integers, it's likely that the roots are also small integers. We try plugging in small integers for x until we find one that makes the polynomial equal to zero.
Step 2 :Once we find one root, we use synthetic division to divide the polynomial by \((x - \text{root})\), which will give us a quadratic polynomial.
Step 3 :We then solve this quadratic equation to find the remaining two roots.
Step 4 :The roots of the polynomial \(p(x)=x^{3}-6 x^{2}+11 x-6\) in increasing sequence are \(\boxed{1, 2, 3}\).