Evaluate.
\[
\begin{array}{l}
16^{\frac{1}{4}}=\square \\
27^{\frac{1}{3}}=\square
\end{array}
\]

Answer

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Answer

So, the fourth root of 16 is \(\boxed{2}\) and the cube root of 27 is \(\boxed{3}\).

Steps

Step 1 ：The question is asking for the fourth root of 16 and the cube root of 27.

Step 2 ：The fourth root of a number is the number that would have to be multiplied by itself 4 times to get the original number. Similarly, the cube root of a number is the number that would have to be multiplied by itself 3 times to get the original number.

Step 3 ：So, the fourth root of 16 is \(\boxed{2}\) and the cube root of 27 is \(\boxed{3}\).

Evaluate.\[\begin{array}{l}16^{\frac{1}{4}}=\square \\27^{\frac{1}{3}}=\square\end{array}\]

Answer

Popular Problems

Evaluate.
\[
\begin{array}{l}
16^{\frac{1}{4}}=\square \\
27^{\frac{1}{3}}=\square
\end{array}
\]