Find the derivative of the following function.
\[
y=2 \cdot 3^{x}
\]
$y^{\prime}=$

Answer

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Answer

$\boxed{y^{\prime} = 2 \cdot 3^{x} \cdot ln(3)}$

Steps

Step 1 ：Use the rule for the derivative of an exponential function, which is $d/dx(a^{x}) = a^{x} \cdot ln(a)$.

Step 2 ：Apply this rule to our function to get: $y^{\prime} = 2 \cdot 3^{x} \cdot ln(3)$.

Step 3 ：$\boxed{y^{\prime} = 2 \cdot 3^{x} \cdot ln(3)}$