Write $y-\frac{2}{3}=\frac{4}{3}(x+2)$ in standard form.

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Answer

$\boxed{4x - 3y = -6}$ is the equation in standard form

Steps

Step 1 ：Given equation is: $y - \frac{2}{3} = \frac{4}{3}(x + 2)$

Step 2 ：Distribute $\frac{4}{3}$ to the terms inside the parentheses: $y - \frac{2}{3} = \frac{4}{3}x + \frac{8}{3}$

Step 3 ：Multiply every term by 3 to eliminate the fractions: $3y - 2 = 4x + 8$

Step 4 ：Rearrange the equation to standard form: $4x - 3y = -6$

Step 5 ：$\boxed{4x - 3y = -6}$ is the equation in standard form