Question 1 (1 point)
Let $f(x)=\left\{\begin{array}{ll}2 x^{4}, & -\pi \leq x< 0 \\ 5 \sin (x), & 0 \leq x \leq \pi\end{array}\right.$. Evaluate the definite integral $\int_{-\pi}^{\pi} f(x) d x$
$\frac{4}{5} \pi^{5}-10$
$8 \pi^{3}-10$
$\frac{2}{5} \pi^{5}+10$
$\frac{4}{5} \pi^{5}$
$\frac{2}{5} \pi^{5}$
Final Answer: \(\boxed{\frac{2}{5} \pi^{5}+10}\)
Step 1 :The given function is a piecewise function, so we will need to calculate the definite integral separately for each piece and then add the results together.
Step 2 :The antiderivative of \(2x^4\) is \(\frac{2}{5}x^5\) and the antiderivative of \(5\sin(x)\) is \(-5\cos(x)\).
Step 3 :We will need to evaluate these at the appropriate points and subtract to find the definite integral.
Step 4 :The definite integral of the function from \(-\pi\) to \(0\) is \(\frac{2}{5}\pi^5\).
Step 5 :The definite integral of the function from \(0\) to \(\pi\) is \(10\).
Step 6 :The definite integral of the function from \(-\pi\) to \(\pi\) is the sum of the definite integrals of the two pieces of the function, which we calculated to be \(10 + \frac{2}{5}\pi^5\).
Step 7 :Final Answer: \(\boxed{\frac{2}{5} \pi^{5}+10}\)