Fif in the blanks so that the resulting statement is true
When solving $\{\begin{array}{l}3x^2+2y^2=35\\ 6x^2+3y^2=47\end{array}$ by the addifion method, we can eliminate $x^2$ by multiplying the first equation by
and then adding the equations.

Step 1 ：The addition method involves manipulating the equations such that when they are added together, one of the variables cancels out. In this case, we want to eliminate $x^2$. To do this, we need to make the coefficients of $x^2$ in both equations equal so that they cancel out when the equations are added together.

Step 2 ：The coefficient of $x^2$ in the first equation is 3 and in the second equation is 6. If we multiply the first equation by 2, the coefficient of $x^2$ in the first equation becomes 6, which is equal to the coefficient of $x^2$ in the second equation.

Step 3 ：Therefore, we should multiply the first equation by 2.

Step 4 ：Final Answer: We should multiply the first equation by $\boxed{{\displaystyle 2}}$.