Solve for the value of \( x \) in the following equation: \(2^{x+3}=32\).
Subtract 3 from both sides of the equation to solve for \(x\), which results in \(x=5-3\).
Step 1 :We know that 32 can be written as \(2^{5}\), so we can rewrite the equation as \(2^{x+3}=2^{5}\).
Step 2 :Since the bases are the same, we can equate the exponents. So, \(x+3=5\).
Step 3 :Subtract 3 from both sides of the equation to solve for \(x\), which results in \(x=5-3\).