Given the function $f(x)=x^{2}-x+6$, find each of the following. $f(8), f(-5), f(0)$
\[
\begin{array}{l}
f(8)=\square \\
f(-5)=\square \\
f(0)=\square
\end{array}
\]
(Simplify your answers. Type an integer or a fraction.)

Answer

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Answer

So, the final answers are $f(8)=\boxed{62}$, $f(-5)=\boxed{36}$, and $f(0)=\boxed{6}$.

Steps

Step 1 ：The function given is $f(x)=x^{2}-x+6$.

Step 2 ：To find $f(8)$, substitute $x=8$ into the function to get $f(8)=8^{2}-8+6=62$.

Step 3 ：To find $f(-5)$, substitute $x=-5$ into the function to get $f(-5)=(-5)^{2}-(-5)+6=36$.

Step 4 ：To find $f(0)$, substitute $x=0$ into the function to get $f(0)=0^{2}-0+6=6$.

Step 5 ：So, the final answers are $f(8)=\boxed{62}$, $f(-5)=\boxed{36}$, and $f(0)=\boxed{6}$.