Problem

Write the sum using sigma notation: $-2-4-8+\ldots-32$
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The sum using sigma notation is $\boxed{\sum_{n=1}^{5} -2*2^{n-1}}$

Steps

Step 1 :Write the sum using sigma notation: $-2-4-8+\ldots-32$

Step 2 :The sum using sigma notation is $\boxed{\sum_{n=1}^{5} -2*2^{n-1}}$

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