Indicate how you would evalutate $f(1), f(2)$ and $f(6)$ for the piecewise function:
\[
f(x)=\left\{\begin{array}{llll}
-x-2 & \text { for } & x \leq 2 & \text { (first function) } \\
x-6 & \text { for } & x> 2 & \text { (second function) }
\end{array}\right.
\]
Which function would you use to evaluate each of the following?
a. $f(1)=$ Select an answer
b. $f(2)=$ Select an answer
c. $f(6)=$ Select an answer
Submit
Answer
Final Answer: \(f(1)=\boxed{-3}\), \(f(2)=\boxed{-4}\), \(f(6)=\boxed{0}\)
Step 1 ：The function f(x) is defined as a piecewise function, which means it has different definitions for different ranges of x.
Step 2 ：To evaluate f(1), since 1 is less than or equal to 2, we use the first function (-x-2). So, f(1) = -1 - 2 = -3.
Step 3 ：To evaluate f(2), since 2 is equal to 2, we also use the first function (-x-2). So, f(2) = -2 - 2 = -4.
Step 4 ：To evaluate f(6), since 6 is greater than 2, we use the second function (x-6). So, f(6) = 6 - 6 = 0.
Step 5 ：Final Answer: \(f(1)=\boxed{-3}\), \(f(2)=\boxed{-4}\), \(f(6)=\boxed{0}\)
