Find the slope of the line tangent to the function \(f(x) = 3x^2 - 2x + 1\) at the point where \(x = 2\).
\(f'(2) = 6*2 - 2 = 10\)
Step 1 :Step 1: Find the derivative of the function \(f(x)\).
Step 2 :\(f'(x) = 6x - 2\)
Step 3 :Step 2: Substitute \(x = 2\) into the derivative to find the slope of the tangent line.
Step 4 :\(f'(2) = 6*2 - 2 = 10\)