Problem

Find $\frac{d y}{d t}$ at $x=3$ and $y=x^{2}+2$ if $\frac{d x}{d t}=5$.

Answer

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Answer

Final Answer: \(\boxed{30}\)

Steps

Step 1 :We are given the function \(y = x^{2} + 2\) and we are asked to find \(\frac{dy}{dt}\) at \(x = 3\) given that \(\frac{dx}{dt} = 5\).

Step 2 :We know that \(\frac{dy}{dt} = \frac{dy}{dx} \cdot \frac{dx}{dt}\) by the chain rule.

Step 3 :So, we first need to find \(\frac{dy}{dx}\), which is the derivative of \(y\) with respect to \(x\).

Step 4 :\(\frac{dy}{dx} = 2x\)

Step 5 :Then we can substitute \(x = 3\) and \(\frac{dx}{dt} = 5\) into the equation to find \(\frac{dy}{dt}\).

Step 6 :\(\frac{dy}{dt} = 2x \cdot \frac{dx}{dt} = 2 \cdot 3 \cdot 5 = 30\)

Step 7 :Final Answer: \(\boxed{30}\)

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