If the variation equation is given as (y = kx^2), and the point ((2,8)) lies on the graph of this equation, what is the constant of variation (k)?

Question

Accepted Answer

Step:1 ：Substitute the given point ((2,8)) into the equation (y = kx^2), we get (8 = k(2^2))Step:2 ：Solving the equation for (k), we get (k = frac{8}{2^2} = frac{8}{4} = 2)

Answer

Step: 1 ：Substitute the given point ((2,8)) into the equation (y = kx^2), we get (8 = k(2^2))Step: 2 ：Solving the equation for (k), we get (k = frac{8}{2^2} = frac{8}{4} = 2)

If the variation equation is given as \(y = kx^2\), and the point \((2,8)\) lies on the graph of this equation, what is the constant of variation \(k\)?

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