Problem

A pair of dice is rolled. Find the probability of rolling
(a) a sum not more than 10 ,
(b) a sum not less than 4 ,
(c) a sum between 3 and 8 (exclusive)
(Type an integer or a simplified fraction.)
(b) How many ways can two dice be rolled such that their sum is not less than 4 ?
$33^{\top}$
(Simplify your answer.)
The probability of rolling a sum not less than 4 is $\frac{11}{12}$.
(Type an integer or a simplified fraction.)
(c) How many ways can two dice be rolled such that their sum is between 3 and 8 (exclusive)?
18
(Simplify your answer.)
The probability of rolling a sum between 3 and 8 (exclusive) is $\square$.
(Type an integer or a simplified fraction.)

Answer

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Answer

Final Answer: The probability of rolling a sum not more than 10 is \(\boxed{\frac{33}{36}}\) or \(\boxed{0.9167}\) when rounded to four decimal places.

Steps

Step 1 :The total number of outcomes when two dice are rolled is 36.

Step 2 :The only sums that are more than 10 when two dice are rolled are 11 and 12.

Step 3 :There are 2 outcomes that result in a sum of 11 and 1 outcome that results in a sum of 12.

Step 4 :Therefore, the number of outcomes that result in a sum not more than 10 is \(36 - 2 - 1 = 33\).

Step 5 :So, the probability of rolling a sum not more than 10 is \(\frac{33}{36}\).

Step 6 :Final Answer: The probability of rolling a sum not more than 10 is \(\boxed{\frac{33}{36}}\) or \(\boxed{0.9167}\) when rounded to four decimal places.

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