Problem

Rewrite $f(x)=\frac{9 x^{3}+2 x-3}{3 x-2}$ in the form Quotient $+\frac{\text { Remalnder }}{\text { Divisor }}$
\[
f(x)=
\]

Answer

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Answer

\[f(x) = \boxed{3x^2 + 2x + 1 + \frac{-2x + 1}{3x - 2}}\]

Steps

Step 1 :The question is asking to rewrite the function \(f(x)\) in the form of Quotient + \(\frac{\text { Remainder }}{\text { Divisor }}\). This is essentially asking to perform polynomial division on the function \(f(x)\). The divisor in this case is \(3x - 2\) and the dividend is \(9x^3 + 2x - 3\). We can perform this division using synthetic division or long division for polynomials.

Step 2 :The quotient and remainder obtained from the division are the final answer. The function \(f(x)\) can be rewritten in the form Quotient + \(\frac{\text { Remainder }}{\text { Divisor }}\) as follows:

Step 3 :\[f(x) = \boxed{3x^2 + 2x + 1 + \frac{-2x + 1}{3x - 2}}\]

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