Problem

Question 1 (1 point)
What is the average rate of change for the function $f(x)=x^{2}+x-7$ over the interval $-2 \leq x \leq 0$ ?

Answer

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Answer

Final Answer: The average rate of change for the function \(f(x)=x^{2}+x-7\) over the interval \(-2 \leq x \leq 0\) is \(\boxed{-1.0}\).

Steps

Step 1 :Given the function \(f(x) = x^{2} + x - 7\) and the interval \([-2, 0]\).

Step 2 :We need to calculate \(f(0)\) and \(f(-2)\).

Step 3 :Substitute \(x = 0\) into the function, we get \(f(0) = 0^{2} + 0 - 7 = -7\).

Step 4 :Substitute \(x = -2\) into the function, we get \(f(-2) = (-2)^{2} + (-2) - 7 = -3\).

Step 5 :The average rate of change of a function over an interval \([a, b]\) is given by the formula: \(\frac{f(b) - f(a)}{b - a}\).

Step 6 :Substitute \(a = -2\), \(b = 0\), \(f(a) = -3\), and \(f(b) = -7\) into the formula, we get \(\frac{-7 - (-3)}{0 - (-2)} = -1.0\).

Step 7 :Final Answer: The average rate of change for the function \(f(x)=x^{2}+x-7\) over the interval \(-2 \leq x \leq 0\) is \(\boxed{-1.0}\).

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