Problem

Given the system of equations: \(3x - 2y = 2\) and \(6x + 4y = 8\), find the slope for each equation.

Answer

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Answer

For the second equation, \(6x + 4y = 8\), we get \(y = -\frac{3}{2}x + 2\). So the slope of the second equation is \(-\frac{3}{2}\).

Steps

Step 1 ：Step 1: Rewrite each equation in slope-intercept form (\(y = mx + b\)). The slope is represented by \(m\).

Step 2 ：For the first equation, \(3x - 2y = 2\), we get \(y = \frac{3}{2}x - 1\). So the slope of the first equation is \(\frac{3}{2}\).

Step 3 ：For the second equation, \(6x + 4y = 8\), we get \(y = -\frac{3}{2}x + 2\). So the slope of the second equation is \(-\frac{3}{2}\).

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