Solve the system of equations by substitution.
\[
\begin{array}{l}
y=6 x-13 \\
3 x+2 y=19
\end{array}
\]
The solution is $\square$.
(Simplify your answer. Type an ordered pair.)
Final Answer: The solution to the system of equations is \(\boxed{(3, 5)}\)
Step 1 :Given the system of equations: \[\begin{array}{l} y=6 x-13 \\ 3 x+2 y=19 \end{array}\]
Step 2 :Substitute the expression for y from the first equation into the second equation: \[3x + 2(6x - 13) = 19\]
Step 3 :Simplify the equation to find the value of x: \[15x - 26 = 19\] which gives \[x = 3\]
Step 4 :Substitute x = 3 back into the first equation to find the value of y: \[y = 6*3 - 13\] which gives \[y = 5\]
Step 5 :Final Answer: The solution to the system of equations is \(\boxed{(3, 5)}\)