A boy owns 8 pairs of pants, 8 shirts, 8 ties, and 4 jackets. How many different outfits can he wear to school if he must wear one of each item?
He can wear different outfits.
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Answer
Final Answer: The boy can wear \(\boxed{2048}\) different outfits to school.
Step 1 ：The boy has a choice of 8 pants, 8 shirts, 8 ties, and 4 jackets.
Step 2 ：The total number of outfits he can wear is the product of the number of choices for each item.
Step 3 ：This is because for each pair of pants, there are 8 shirts, 8 ties, and 4 jackets he can choose to wear with it.
Step 4 ：This is a basic principle of counting in combinatorics.
Step 5 ：Using the formula for combinations, we get \(8 \times 8 \times 8 \times 4 = 2048\).
Step 6 ：Final Answer: The boy can wear \(\boxed{2048}\) different outfits to school.
