$A(t)=232(2.92)^{t}$, where $t=0$ corresponds to 2006 . How many outlets were avallable in 2008 , in 2010, in 2011?
The number of outiets avalable in the year 2008 was approximately (Simplify your answer. Round to the nearest integer as needed)
Answer
Final Answer: \(\boxed{1978}\)
Step 1 ：The given function is an exponential function, where 't' is the time in years since 2006 and 'A(t)' is the number of outlets. To find the number of outlets in 2008, we need to substitute 't' with 2 (since 2008 is 2 years after 2006) in the given function and calculate the result.
Step 2 ：\(A(2)=232(2.92)^{2}\)
Step 3 ：Calculate the above expression to get the number of outlets in 2008.
Step 4 ：The number of outlets available in the year 2008 was approximately 1978.
Step 5 ：Final Answer: \(\boxed{1978}\)
