For the given confidence level and values of $x$ and $n$, find the following.
\[
x=44, n=99, \text { confidence tevel } 98 \%
\]

Part: $0 / 3$

Part 1 of 3
(a) Find the point estimate. Round the answers to at least four decimal places, if necessary.

The point estimate for the given data is 0.4444

Part: $1 / 3$

Part 2 of 3
(b) Find the standard error. Round the answers to at least four decimal places, if necessary.

The standard error for the given data is $\square$.

Answer

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Answer

$\boxed{0.0500}$ is the standard error for the given data.

Steps

Step 1 ：Calculate the point estimate as the sample proportion, which is $x/n$. Given that $x=44$ and $n=99$, the point estimate is $44/99 = 0.4444$.

Step 2 ：Calculate the standard error (SE) of the sample proportion as $\sqrt{p(1-p)/n}$, where $p$ is the point estimate.

Step 3 ：Substitute the values into the formula to get the standard error as $\sqrt{0.4444*(1-0.4444)/99} = 0.0500$.

Step 4 ：$\boxed{0.0500}$ is the standard error for the given data.