Find the nth term of the arithmetic sequence with the given values.
\[
a_{1}=\frac{5}{3}, d=\frac{1}{6}, n=618
\]
The 618 th term is $a_{618}=$
( Simplify your answer. Type an integer or a fraction.)
Answer
Final Answer: The 618th term of the arithmetic sequence is \(a_{618} = \boxed{\frac{209}{2}}\).
Step 1 ：Given the first term of the arithmetic sequence \(a_{1} = \frac{5}{3}\), the common difference \(d = \frac{1}{6}\), and the term number \(n = 618\).
Step 2 ：The nth term of an arithmetic sequence can be found using the formula: \(a_{n} = a_{1} + (n-1) * d\).
Step 3 ：Substitute the given values into the formula to find the 618th term: \(a_{618} = \frac{5}{3} + (618-1) * \frac{1}{6}\).
Step 4 ：Simplify the expression to get the final answer: \(a_{618} = \frac{209}{2}\).
Step 5 ：Final Answer: The 618th term of the arithmetic sequence is \(a_{618} = \boxed{\frac{209}{2}}\).
