Find the nth term of the arithmetic sequence with the given values.
$a_{1} = \frac{5}{3}, d = \frac{1}{6}, n = 618$
The 618 th term is $a_{618} =$
( Simplify your answer. Type an integer or a fraction.)

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Final Answer: The 618th term of the arithmetic sequence is $a_{618} = \frac{209}{2}$ .

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Step 1 ：Given the first term of the arithmetic sequence $a_{1} = \frac{5}{3}$ , the common difference $d = \frac{1}{6}$ , and the term number $n = 618$ .

Step 2 ：The nth term of an arithmetic sequence can be found using the formula: $a_{n} = a_{1} + (n - 1) * d$ .

Step 3 ：Substitute the given values into the formula to find the 618th term: $a_{618} = \frac{5}{3} + (618 - 1) * \frac{1}{6}$ .

Step 4 ：Simplify the expression to get the final answer: $a_{618} = \frac{209}{2}$ .

Step 5 ：Final Answer: The 618th term of the arithmetic sequence is $a_{618} = \frac{209}{2}$ .

Find the nth term of the arithmetic sequence with the given values.a1=53,d=16,n=618The 618 th term is a618=( Simplify your answer. Type an integer or a fraction.)

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Find the nth term of the arithmetic sequence with the given values.
$a_{1} = \frac{5}{3}, d = \frac{1}{6}, n = 618$
The 618 th term is $a_{618} =$
( Simplify your answer. Type an integer or a fraction.)