Part 4 of 4
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Determine the area under the standard normal curve that lies to the left of (a) $Z=-0.22$, (b) $Z=-0.67$, (c) $Z=-0.38$, and $(d) Z=-0.96$.
(a) The area to the left of $Z=-0.22$ is 0.4129 .
(Round to four decimal places as needed.)
(b) The area to the left of $Z=-0.67$ is 0.2514 .
(Round to four decimal places as needed.)
(c) The area to the left of $Z=-0.38$ is 0.3520 .
(Round to four decimal places as needed.)
(d) The area to the left of $Z=-0.96$ is $\square$.
(Round to four decimal places as needect)
Incorrect: 0
Answer
Final Answer: The area to the left of \(Z=-0.96\) is \(\boxed{0.1685}\).
Step 1 ：The problem is asking for the area under the standard normal curve that lies to the left of \(Z=-0.96\). This is equivalent to finding the cumulative distribution function (CDF) at \(Z=-0.96\) for a standard normal distribution. The standard normal distribution has a mean of 0 and a standard deviation of 1.
Step 2 ：By calculating, we find that the area is approximately 0.16852760746683781.
Step 3 ：Final Answer: The area to the left of \(Z=-0.96\) is \(\boxed{0.1685}\).
