Problem

Find all roots of the polynomial 2x33x25x+6

Answer

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Answer

Step 5: Therefore, the roots of the polynomial 2x33x25x+6 are 1, -2, and 3.

Steps

Step 1 :Step 1: Identify the coefficients of the polynomial and list them. The coefficients are 2, -3, -5, and 6.

Step 2 :Step 2: List the factors of the constant term (6) and the leading coefficient (2). The factors of 6 are ±1,±2,±3,±6 and the factors of 2 are ±1,±2.

Step 3 :Step 3: Form the ratio of each factor of the constant term to each factor of the leading coefficient. The potential rational roots are ±1,±2,±3,±6,±12,±32.

Step 4 :Step 4: Substitute each potential root into the polynomial until you find one that makes the polynomial equal to zero. After testing, we find that 1, -2 and 3 are roots of the polynomial.

Step 5 :Step 5: Therefore, the roots of the polynomial 2x33x25x+6 are 1, -2, and 3.

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