Find a possible formula for the general $n^{\text{th }}$ term of the sequence that begins as follows. Please simplify your solution.
$$4,16,64,256,1024,\dots$$

Step 1 ：The given sequence appears to be a geometric sequence, where each term is multiplied by a constant to get the next term.

Step 2 ：To find the general nth term of a geometric sequence, we can use the formula: $a_n=a_1\ast r^{(n-1)}$ where: $a_n$ is the nth term of the sequence, $a_1$ is the first term of the sequence, $r$ is the common ratio (the constant that each term is multiplied by to get the next term), and $n$ is the term number.

Step 3 ：From the given sequence, we can see that the first term $a_1$ is 4, and the common ratio $r$ is 4 (since each term is 4 times the previous term).

Step 4 ：So, we can substitute these values into the formula to find the general nth term of the sequence.

Step 5 ：$\boxed{{\displaystyle a_n=4\ast 4^{(n-1)}}}$ is the general nth term of the sequence.