Factor the trinomial.
$w^{2} - 6 w x + 8 x^{2}$

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Answer

$(w - 2 x) (w - 4 x)$ is the factored form of the trinomial $w^{2} - 6 w x + 8 x^{2}$ .

Steps

Step 1 ：To factor the trinomial $w^{2} - 6 w x + 8 x^{2}$ , we need to find two numbers that multiply to 8 (the coefficient of $x^{2}$ ) and add to -6 (the coefficient of $w x$ ).

Step 2 ：The numbers that satisfy these conditions are -2 and -4.

Step 3 ：Therefore, we can write the trinomial as: $w^{2} - 6 w x + 8 x^{2} = (w - 2 x) (w - 4 x)$ .

Step 4 ： $(w - 2 x) (w - 4 x)$ is the factored form of the trinomial $w^{2} - 6 w x + 8 x^{2}$ .

Factor the trinomial.w2−6wx+8x2

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Factor the trinomial.
$w^{2} - 6 w x + 8 x^{2}$