Solve for the variable x.:
$\begin{array}{c}3 x-y=4 \\ 2 x-3 y=-9\end{array}$
\(\boxed{x = 3}\)
Step 1 :Given the system of equations: \(3x - y = 4\) and \(2x - 3y = -9\)
Step 2 :Multiply the first equation by 3 and the second equation by 1 to make the coefficients of y the same in both equations: \(9x - 3y = 12\) and \(2x - 3y = -9\)
Step 3 :Subtract the second equation from the first: \((9x - 2x) - (3y - 3y) = 12 - (-9)\)
Step 4 :This simplifies to: \(7x = 21\)
Step 5 :Solve for x by dividing both sides by 7: \(x = \frac{21}{7}\)
Step 6 :\(\boxed{x = 3}\)