Use De Morgan's laws to write the negation of the statement below Express the negation in a form such that the symbol $\sim$ negates only simple statements
$\sim p \land (q \to\sim r)$

The negation of $\sim p \land (q \to\sim r)$ is $◻$

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Final Answer: The negation of $\sim p \land (q \to\sim r)$ is $p \lor (q \land r)$ .

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Step 1 ：De Morgan's laws state that the negation of a conjunction is the disjunction of the negations, and the negation of a disjunction is the conjunction of the negations. In other words, $\sim (p \land q) =\sim p \lor \sim q$ and $\sim (p \lor q) =\sim p \land \sim q$ .

Step 2 ：In this case, we have a conjunction $\sim p \land (q \to\sim r)$ . So, we can apply De Morgan's law to get the negation of this statement.

Step 3 ：Also, we need to remember that the negation of an implication $p \to q$ is $p \land \sim q$ .

Step 4 ：So, the negation of $\sim p \land (q \to\sim r)$ is $p \lor \sim (q \to\sim r)$ , which simplifies to $p \lor (q \land r)$ .

Step 5 ：Final Answer: The negation of $\sim p \land (q \to\sim r)$ is $p \lor (q \land r)$ .

Use De Morgan's laws to write the negation of the statement below Express the negation in a form such that the symbol ∼ negates only simple statements∼p∧(q→∼r) The negation of ∼p∧(q→∼r) is ◻

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Use De Morgan's laws to write the negation of the statement below Express the negation in a form such that the symbol $\sim$ negates only simple statements
$\sim p \land (q \to\sim r)$

The negation of $\sim p \land (q \to\sim r)$ is $◻$