(Volume MC)

A tent is shaped like a hexagonal pyramid The area of the hexagonal base is equal to $64.95 \mathrm{t}^{2}$, and the volume of the tent is $346.41 \mathrm{ft}^{3}$ What is the height of the tent, rounded to the nearest foot?
8. ofeet
53 feel
17.4 feel
16 o feet

Step 1 ：The volume of a pyramid is given by the formula \(V = \frac{1}{3} \times \text{base_area} \times \text{height}\). We know the volume and the base area, so we can rearrange the formula to solve for the height: \(\text{height} = \frac{3 \times \text{volume}}{\text{base_area}}\).

Step 2 ：Substitute the given values into the formula: \(\text{base_area} = 64.95\) and \(\text{volume} = 346.41\).

Step 3 ：Calculate the height: \(\text{height} = \frac{3 \times 346.41}{64.95} = 16.000461893764435\).

Step 4 ：Round the result to the nearest foot: \(\text{height_rounded} = 16\).

Step 5 ：Final Answer: The height of the tent, rounded to the nearest foot, is \(\boxed{16}\) feet.