Solve for variable 'x' in the given system of equations:
32.
\[
\begin{array}{l}
x-4 y=-20 \\
8 x-3 y=-15
\end{array}
\]

Step 1 ：Given the system of equations: \[ \begin{array}{l} x-4 y=-20 \ 8 x-3 y=-15 \end{array} \]

Step 2 ：First, multiply the first equation by 8 and the second equation by 1 to make the coefficients of 'x' in both equations equal.

Step 3 ：This gives us: \[ \begin{array}{l} 8x-32 y=-160 \ 8 x-3 y=-15 \end{array} \]

Step 4 ：Subtract the second equation from the first to eliminate 'x' and solve for 'y'.

Step 5 ：This gives us: \(29y = -145\), so \(y = -145 / 29 = 5\)

Step 6 ：Substitute \(y = 5\) into the first equation to find the value of 'x'.

Step 7 ：This gives us: \(x - 4*5 = -20\), so \(x = -20 + 20 = 0\)

Step 8 ：The solution to the system of equations is \(x = 0\) and \(y = 5\).

Step 9 ：Final Answer: \(\boxed{0}\)