Let $g (x) = \int_{4}^{x} (5 + \sqrt{t}) d t$ . Find $g^{'} (x)$ .
$g^{'} (x) =$

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Therefore, the final answer is $g^{'} (x) = 5 + \sqrt{x}$ .

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Step 1 ：Let $g (x) = \int_{4}^{x} (5 + \sqrt{t}) d t$ .

Step 2 ：By the Fundamental Theorem of Calculus, the derivative of the integral of a function from a constant to x is just the function evaluated at x.

Step 3 ：So, $g^{'} (x) = 5 + \sqrt{x}$ .

Step 4 ：Therefore, the final answer is $g^{'} (x) = 5 + \sqrt{x}$ .

Let g(x)=∫4x(5+t)dt. Find g′(x).g′(x)=

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Let $g (x) = \int_{4}^{x} (5 + \sqrt{t}) d t$ . Find $g^{'} (x)$ .
$g^{'} (x) =$