(a) Write the equation in exponential form.
(b) Solve the equation from part (a).
(c) Verify that the solution checks in the original equation.
\[
\log _{3}(3 x-3)=2
\]

Part: $\mathbf{0} / \mathbf{3}$

Part 1 of 3
(a) The equation in exponential form is $\square$.

Answer

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Answer

Verify that the solution checks in the original equation: $\log _{3}(3 \cdot (3^2 + 3)/3)=2$

Steps

Step 1 ：Write the equation in exponential form: $3^2 = 3x - 3$

Step 2 ：Solve the equation from part (a): $3x = 3^2 + 3$

Step 3 ：Verify that the solution checks in the original equation: $\log _{3}(3 \cdot (3^2 + 3)/3)=2$