Solve the equation \(2^{\cos x} = 8\) for \(x\), given that \(0 \leq x \leq 2\pi\).
Step 4: Since the range of the cosine function is \([-1, 1]\), there is no solution for this equation.
Step 1 :Step 1: Take the natural logarithm on both sides: \(\ln(2^{\cos x}) = \ln 8\).
Step 2 :Step 2: Use the property of logarithms to bring the exponent to the front: \(\cos x \cdot \ln 2 = \ln 8\).
Step 3 :Step 3: Note that \(\ln 8 = 3 \ln 2\), so the equation simplifies to \(\cos x = 3\).
Step 4 :Step 4: Since the range of the cosine function is \([-1, 1]\), there is no solution for this equation.