Find possible values of $a$ and $b$ that make the statement true.
$\begin{array}{r} \int_{- 3}^{3} f (x) d x + \int_{3}^{8} f (x) d x - \int_{a}^{b} f (x) d x = \int_{- 1}^{8} f (x) d x \\ (a, b) = (◻) \end{array}$

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Final Answer: The possible values of a and b that make the statement true are $(- 3, - 1)$ .

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Step 1 ：The integral of a function from a to b is the area under the curve of the function from a to b. The integral from -3 to 3 plus the integral from 3 to 8 is the area under the curve from -3 to 8. The integral from -1 to 8 is the area under the curve from -1 to 8. The difference between these two areas is the area under the curve from -3 to -1. Therefore, the integral from a to b must be the integral from -3 to -1. So, a = -3 and b = -1.

Step 2 ：Final Answer: The possible values of a and b that make the statement true are $(- 3, - 1)$ .

Find possible values of a and b that make the statement true.∫−33f(x)dx+∫38f(x)dx−∫abf(x)dx=∫−18f(x)dx(a,b)=(◻)

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Find possible values of $a$ and $b$ that make the statement true.
$\begin{array}{r} \int_{- 3}^{3} f (x) d x + \int_{3}^{8} f (x) d x - \int_{a}^{b} f (x) d x = \int_{- 1}^{8} f (x) d x \\ (a, b) = (◻) \end{array}$