Problem

Find $\frac{d y}{d x}$ by implicit differentiation.
\[
\begin{array}{r}
x^{7}-x y^{4}+y^{7}=1 \\
\frac{d y}{d x}=\square
\end{array}
\]

Answer

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Answer

Final Answer: \(\boxed{\frac{y^4 - 7x^6}{-4xy^3 + 7y^6}}\)

Steps

Step 1 :Differentiate both sides of the equation with respect to x

Step 2 :Apply the chain rule and product rule to the left side

Step 3 :Simplify the equation

Step 4 :Solve for dy/dx

Step 5 :Final Answer: \(\boxed{\frac{y^4 - 7x^6}{-4xy^3 + 7y^6}}\)

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