$1 \leftarrow$ Solve $\frac{1}{A}=\frac{1}{v}+\frac{1}{p}$ for $p$
So, the solution to the equation \(\frac{1}{A}=\frac{1}{v}+\frac{1}{p}\) for \(p\) is \(\boxed{p = \frac{Av}{A - v}}\).
Step 1 :Start with the equation \(\frac{1}{A}=\frac{1}{v}+\frac{1}{p}\).
Step 2 :Subtract \(\frac{1}{v}\) from both sides to get \(\frac{1}{p} = \frac{1}{A} - \frac{1}{v}\).
Step 3 :Take the reciprocal of both sides to isolate \(p\), giving \(p = \frac{1}{\frac{1}{A} - \frac{1}{v}}\).
Step 4 :Simplify the right side of the equation to get \(p = \frac{Av}{A - v}\).
Step 5 :So, the solution to the equation \(\frac{1}{A}=\frac{1}{v}+\frac{1}{p}\) for \(p\) is \(\boxed{p = \frac{Av}{A - v}}\).