Factoring a perfect square trinomial with leading coefficlent 1
Factor.
\[
w^{2}+8 w+16
\]
\(\boxed{(w + 4)^2}\) is the final answer.
Step 1 :Define the variable \(w\).
Step 2 :Define the trinomial \(w^{2}+8 w+16\).
Step 3 :Define the factored form \((w + 4)^2\).
Step 4 :Check if the trinomial is equal to the factored form.
Step 5 :The trinomial \(w^{2}+8 w+16\) is indeed equal to the factored form \((w + 4)^2\). Therefore, the trinomial can be factored into \((w + 4)^2\).
Step 6 :\(\boxed{(w + 4)^2}\) is the final answer.