Problem

core: $20.69 / 30 \quad 29 / 30$ answered
Question 3
$\mho_{1 / 1}$ pt $\bigcirc_{2}$
If the area to the left of $x$ in a normal distribution is 0.789, what is the area to the right of $x$ ?
Answer:

If the area to the right of $x$ in a normal distribution is 0.789, what is the area to the left of $x$ ?
Answer:
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Final Answer: The area to the right of $x$ is \( \boxed{0.211} \).

Steps

Step 1 :The area under the curve of a normal distribution sums up to 1. Therefore, if the area to the left of x is 0.789, the area to the right of x would be 1 - 0.789.

Step 2 :Similarly, if the area to the right of x is 0.789, the area to the left of x would be 1 - 0.789.

Step 3 :Let's calculate the area to the right of x when the area to the left of x is 0.789.

Step 4 :left_area = 0.789

Step 5 :right_area = 1 - left_area = 1 - 0.789 = 0.211

Step 6 :Final Answer: The area to the right of $x$ is \( \boxed{0.211} \).

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