Problem

Differentiate the function.
\[
\begin{array}{l}
y=e^{k \tan \sqrt{3 x}} \\
y^{\prime}(x)=
\end{array}
\]

Answer

Expert–verified
Hide Steps
Answer

\(\boxed{y^{\prime}(x)=\frac{\sqrt{3}k(\tan(\sqrt{3}\sqrt{x})^2 + 1)e^{k\tan(\sqrt{3}\sqrt{x})}}{2\sqrt{x}}}\) is the final answer.

Steps

Step 1 :Given the function \(y=e^{k \tan \sqrt{3 x}}\), we are asked to find its derivative.

Step 2 :To find the derivative of the function, we need to use the chain rule. The chain rule is a formula to compute the derivative of a composite function. The outer function is the exponential function and the inner function is \(k \tan \sqrt{3x}\).

Step 3 :We first differentiate the outer function and then multiply it by the derivative of the inner function.

Step 4 :Applying the chain rule, we get the derivative of the function as \(\frac{\sqrt{3}k(\tan(\sqrt{3}\sqrt{x})^2 + 1)e^{k\tan(\sqrt{3}\sqrt{x})}}{2\sqrt{x}}\).

Step 5 :\(\boxed{y^{\prime}(x)=\frac{\sqrt{3}k(\tan(\sqrt{3}\sqrt{x})^2 + 1)e^{k\tan(\sqrt{3}\sqrt{x})}}{2\sqrt{x}}}\) is the final answer.

link_gpt