Problem

Express the confidence interval $(362.7,520.1)$ in the form of $\bar{x} \pm M E$.
\[
\bar{x} \pm M E=\square \pm
\]
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Answer

So, the confidence interval \((362.7,520.1)\) in the form of \(\bar{x} \pm M E\) is \(\boxed{441.4 \pm 78.7}\).

Steps

Step 1 :The confidence interval is given as \((362.7,520.1)\). This means that the lower limit of the interval is \(362.7\) and the upper limit is \(520.1\).

Step 2 :The midpoint of this interval is the mean \(\bar{x}\) and the margin of error \(ME\) is the distance from the mean to either end of the interval.

Step 3 :To find the mean \(\bar{x}\), we can add the lower and upper limits and divide by 2.

Step 4 :To find the margin of error \(ME\), we can subtract the lower limit from the mean.

Step 5 :Calculating these values, we find that the mean \(\bar{x}\) is \(441.4\) and the margin of error \(ME\) is approximately \(78.7\).

Step 6 :So, the confidence interval \((362.7,520.1)\) in the form of \(\bar{x} \pm M E\) is \(\boxed{441.4 \pm 78.7}\).

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