Problem

In Exercises 4 and 5 , use the graphs of $f$ and $h$ to describe the transformation from the graph of $f$ to the grap of $h$.
\[
f(x)=\frac{1}{3} x+1 ; h(x)=-f(x)
\]

Answer

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Answer

\(\boxed{\text{The graph of } h(x) \text{ is the graph of } f(x) \text{ reflected in the x-axis}}\)

Steps

Step 1 :Given the functions \(f(x)=\frac{1}{3} x+1\) and \(h(x)=-f(x)\)

Step 2 :Substitute \(f(x)\) into \(h(x)\) to get \(h(x)=-\frac{1}{3} x-1\)

Step 3 :The negative sign in front of the function \(f(x)\) in the definition of \(h(x)\) indicates a reflection in the x-axis

Step 4 :This means that every point \((x, y)\) on the graph of \(f\) is transformed to the point \((x, -y)\) on the graph of \(h\)

Step 5 :\(\boxed{\text{The graph of } h(x) \text{ is the graph of } f(x) \text{ reflected in the x-axis}}\)

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