b: $y$-intercept or starting
\begin{tabular}{|c|c|}
\hline$X$ & $Y$ \\
\hline 0 & 3 \\
\hline 1 & 7 \\
\hline 2 & 11 \\
\hline 3 & 15 \\
\hline
\end{tabular}

What is the rate?

What is the starting value?

Write the equation:

Step 1 ：The question is asking for the rate and the starting value of a linear function represented by the given table. The rate of a linear function is the slope, which can be calculated by taking the difference in the y-values divided by the difference in the x-values. The starting value is the y-intercept, which is the y-value when x is 0.

Step 2 ：From the table, we can see that the x-values are [0, 1, 2, 3] and the corresponding y-values are [3, 7, 11, 15].

Step 3 ：By calculating the difference in the y-values divided by the difference in the x-values, we find that the rate is \(4.0\).

Step 4 ：The starting value is the y-value when x is 0, which is \(3\) from the table.

Step 5 ：Final Answer: The rate is \(\boxed{4}\) and the starting value is \(\boxed{3}\). The equation of the line is \(y = 4x + 3\).