Suppose $C(x)=x^{2}-8 x+18$ represents the costs, in hundreds, to produce $x$ thousand pens. How many pens should be produced to minimize the cost? What is the minimum cost?

Number of pens to minimize cost: $\square$ pens
Minimum cost: $\square$ dollars
You have 3 attempt(s) remaining before you will receive a new version of this problem.

Step 1 ：Define the coefficients of the quadratic function: \(a = 1\), \(b = -8\), \(c = 18\).

Step 2 ：Calculate the number of pens to minimize cost using the formula \(x = -\frac{b}{2a}\). Substituting the values of \(a\) and \(b\) into the formula, we get \(x = 4.0\). This means 4000 pens should be produced to minimize the cost.

Step 3 ：Calculate the minimum cost by substituting \(x\) into the quadratic function: \(min\_cost = a*x^2 + b*x + c\). Substituting the values of \(a\), \(b\), \(c\), and \(x\) into the formula, we get \(min\_cost = 2.0\). This means the minimum cost is 200 dollars.

Step 4 ：Final Answer: The number of pens to minimize cost is \(\boxed{4000}\) pens and the minimum cost is \(\boxed{200}\) dollars.