For each value of $x$, determine whether it is a solution to $1-4 x=25$.
\begin{tabular}{|c|c|c|}
\hline \multirow{2}{*}{$x$} & \multicolumn{2}{|c|}{\begin{tabular}{c}
Is it a \\
solution?
\end{tabular}} \\
\cline { 2 - 3 } & Yes & No \\
\hline 2 & 0 & 0 \\
\hline-6 & 0 & 0 \\
\hline-3 & 0 & 0 \\
\hline 5 & 0 & 0 \\
\hline
\end{tabular}

Step 1 ：Given the equation \(1-4x=25\), we are asked to determine whether each given value of \(x\) is a solution to the equation.

Step 2 ：To do this, we substitute each value of \(x\) into the equation and see if the equation holds true.

Step 3 ：If it does, then the value of \(x\) is a solution to the equation. If it does not, then the value of \(x\) is not a solution to the equation.

Step 4 ：Substituting \(x=2\) into the equation, we get \(1-4*2=25\), which simplifies to \(-7=25\). This is not true, so \(x=2\) is not a solution to the equation.

Step 5 ：Substituting \(x=-6\) into the equation, we get \(1-4*(-6)=25\), which simplifies to \(25=25\). This is true, so \(x=-6\) is a solution to the equation.

Step 6 ：Substituting \(x=-3\) into the equation, we get \(1-4*(-3)=25\), which simplifies to \(13=25\). This is not true, so \(x=-3\) is not a solution to the equation.

Step 7 ：Substituting \(x=5\) into the equation, we get \(1-4*5=25\), which simplifies to \(-19=25\). This is not true, so \(x=5\) is not a solution to the equation.

Step 8 ：From the above, we can conclude that only \(x=-6\) is a solution to the equation \(1-4x=25\).

Step 9 ：Final Answer: \(\boxed{x=-6}\)