Problem

Find the expanded form of the circle equation with center at point (h,k)=(3,4) and radius r=5

Answer

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Answer

Simplify the equation to get x2+y2+6x8y=0.

Steps

Step 1 :We know that the standard equation of a circle is (xh)2+(yk)2=r2, where (h,k) is the center and r is the radius of the circle.

Step 2 :Substitute h=3, k=4, and r=5 into the equation to get (x(3))2+(y4)2=52 or (x+3)2+(y4)2=25.

Step 3 :Expand the equation to get x2+6x+9+y28y+16=25.

Step 4 :Simplify the equation to get x2+y2+6x8y=0.

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