Find the expanded form of the circle equation with center at point (h,k)=(−3,4) and radius r=5
Simplify the equation to get x2+y2+6x−8y=0.
Step 1 :We know that the standard equation of a circle is (x−h)2+(y−k)2=r2, where (h,k) is the center and r is the radius of the circle.
Step 2 :Substitute h=−3, k=4, and r=5 into the equation to get (x−(−3))2+(y−4)2=52 or (x+3)2+(y−4)2=25.
Step 3 :Expand the equation to get x2+6x+9+y2−8y+16=25.
Step 4 :Simplify the equation to get x2+y2+6x−8y=0.