Find the equation of the line which passes through the point $(-2,-3)$, and is parallel to the line with the equation $y=-\frac{1}{2} x-1$. Express your answer in slope-intercept form. Simplify your answer.
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Step 1 ：Given a point (-2,-3) and a line with the equation \(y=-\frac{1}{2} x-1\), we need to find the equation of a line that passes through the given point and is parallel to the given line.

Step 2 ：Since parallel lines have the same slope, the slope \(m\) of the line we are looking for is also -1/2.

Step 3 ：Substitute the point (-2,-3) into the equation \(y = mx + b\) to solve for \(b\).

Step 4 ：Substituting gives us \(-3 = -\frac{1}{2}*(-2) + b\), which simplifies to \(-3 = 1 + b\).

Step 5 ：Solving for \(b\) gives us \(b = -4\).

Step 6 ：So, the equation of the line is \(y = -\frac{1}{2}x - 4\).

Step 7 ：Final Answer: The equation of the line is \(\boxed{y = -\frac{1}{2}x - 4}\).