Discrete probability distribution: Basic
Fill in the $P(X=x)$ values to give a legitimate probability distribution for the discrete random variable $X$, whose possible values are $-5,-4,4,5$, and 6
\begin{tabular}{|c|c|}
\hline Value $x$ of $X$ & $P(X=x)$ \\
\hline-5 & $\square$ \\
\hline-4 & $\square$ \\
\hline 4 & 0.29 \\
\hline 5 & 0.30 \\
\hline 6 & 0.21 \\
\hline
\end{tabular}
Explanation
Check
Answer
The probabilities for \(X=-5\) and \(X=-4\) are both \(\boxed{0.10}\).
Step 1 ：The sum of all probabilities in a probability distribution must equal 1. We already know the probabilities for \(X=4,5,6\) which sum up to \(0.29+0.30+0.21=0.80\).
Step 2 ：Therefore, the sum of probabilities for \(X=-5,-4\) must be \(1-0.80=0.20\).
Step 3 ：We can distribute this remaining probability equally among \(X=-5,-4\) for simplicity, but any distribution that sums to \(0.20\) would be valid.
Step 4 ：The probabilities for \(X=-5\) and \(X=-4\) are both \(\boxed{0.10}\).
