Solve for $x$.
\[
\begin{array}{l}
\sqrt[3]{3 x-4}=3 \\
x=
\end{array}
\]

Answer

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Answer

$\boxed{x = \frac{31}{3}}$

Steps

Step 1 ：$(\sqrt[3]{3x-4})^3 = 3^3$

Step 2 ：$3x - 4 = 27$

Step 3 ：$3x = 27 + 4$

Step 4 ：$3x = 31$

Step 5 ：$x = \frac{31}{3}$

Step 6 ：$\sqrt[3]{3(\frac{31}{3})-4} = 3$

Step 7 ：$\sqrt[3]{31-4} = 3$

Step 8 ：$\sqrt[3]{27} = 3$

Step 9 ：$\boxed{x = \frac{31}{3}}$