Problem

A store carries four brands of $C D$ players, J, G, P, and S. From past records, the manager found that the relative frequency of brand choice among customers varied. Which of the following probability assignments for a particular customer choosing a particular brand of $C D$ player would have to be rejected? Why?
(A) $P(J)=0.10, P(G)=0.47, P(P)=0.29, P(S)=0.57$
(B) $P(J)=0.17, P(G)=0.45, P(P)=0.24, P(S)=0.14$
(C) $P(J)=0.36, P(G)=-0.12, P(P)=0.23, P(S)=0.53$
Should probability assignment (A) be rejected? Why or why not?
A. No, because each probability is between 0 and 1 (inclusive), and the sum of theprobabilites is 1 .
B. Yes, because one of the probabilities is negative.
C. Yes, because the sum of all the events is not 1.
D. Yes, because each probability is between 0 and 1 (inclusive), and the sum of the probabilities is 1 .

Answer

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Answer

Final Answer: \(\boxed{\text{(C) Yes, because the sum of all the events is not 1.}}\)

Steps

Step 1 :Assign the given probabilities to each brand: \(P(J) = 0.10\), \(P(G) = 0.47\), \(P(P) = 0.29\), \(P(S) = 0.57\).

Step 2 :Calculate the total probability: \(P(J) + P(G) + P(P) + P(S) = 1.43\).

Step 3 :Since the total probability is not equal to 1, the probability assignment (A) should be rejected.

Step 4 :Final Answer: \(\boxed{\text{(C) Yes, because the sum of all the events is not 1.}}\)

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